SUM SERIES
SUM OF SERIES 1.SUM OF SERIES 1+1/2+1/3+1....1/N #include <stdio.h> main () { int i , n ; float sum = 0 ; printf ( "Enter value of n\n" ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { sum +=( float ) 1 / i ; } printf ( "The value of\n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "1/%d+ " , i ); } else { printf ( "1/%d= " , i ); } } printf ( "%f\n" , sum ); } •Output Enter value of n 8 The value of 1/1+ 1/2+ 1/3+ 1/4+ 1/5+ 1/6+ 1/7+ 1/8= 2.717857 2.SUM OF SERIES 1/1!+1/2!+1/3!+1....+N /N! main() { int i,n; float sum=0; printf("Enter value of n\n"); scanf("%d",&n); for(i=1;i<=n;i++) { sum+=(float)i/factorial(i); } printf("The value of\n"); for(i=1;i<=n;i++) { if(i<n) { printf("%d/%d!+ ",i,i); } else { printf("%d/%d!= ",i,i); } } pri...